Question

Two equal forces are creting perpenclicular to each
other. Their refultant force is 14.14 N. Find the
magnitude of each force​

Answer 1

Given :

Two equal acts on the body perpendicular to each other. Their resultant is 14.14N.

To Find :

Magnitude of each force.

Solution :

❖ By triangle law or parallelogram law of vector addition, the magnitude of resultant R at two forces F₁ and F₂ inclined to each other at angle θ, is given by

• R² = F₁² + F₂² + 2F₁F₂ cosθ

Here, F₁ = F₂ = F

By substituting the given values;

➙ (14.14)² = F² + F² + 2(F)(F) cos90°

➙ 200 = 2F² + 2F² (0)

➙ F² = 200/2

➙ F = √100

➙ F = 10 N

Knowledge BoosteR :

• The latin word vector means carrier.
• The physical quantities which have no specified direction and have different values in different directions are called tensors. For example moment of inertia$.$
• Null vector is a vector which has zero magnitude and an arbitrary direction.
• Negative vector of a given vector is a vector of same magnitude but acting in a direction opposite to that of the given vector.
• A vector whose initial point is fixed is called a localised vector and whose initial point is not fixed is called non-localised vector.

Answer 2

$\huge\colorbox{yellow}{Áηѕωєя࿐❤}$

Given :

Two equal acts on the body perpendicular to each other. Their resultant is 14.14N.

To Find :

Magnitude of each force.

Solution :

❖ By triangle law or parallelogram law of vector addition, the magnitude of resultant R at two forces F₁ and F₂ inclined to each other at angle θ, is given by

• R² = F₁² + F₂² + 2F₁F₂ cosθ

Here, F₁ = F₂ = F

By substituting the given values;

➙ (14.14)² = F² + F² + 2(F)(F) cos90°

➙ 200 = 2F² + 2F² (0)

➙ F² = 200/2

➙ F = √100

➙ F = 10 N

Hope it helps :)