two equal forces have their resultant equal to either at what angle are there inclined
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They will inclined at 120°
Let θ be the angle between the two vectors A and B such that, |A| = |B|.
Therefore,
R 2 = A 2 + B 2 + 2AB cosθ
=> A 2 = A 2 + A 2 + 2(A)(A) cosθ [since, |A| = |B| = |R|]
=> A 2 = 2A 2 + 2A 2 cosθ
=> cosθ = -1/2
=> θ = 120°
Let θ be the angle between the two vectors A and B such that, |A| = |B|.
Therefore,
R 2 = A 2 + B 2 + 2AB cosθ
=> A 2 = A 2 + A 2 + 2(A)(A) cosθ [since, |A| = |B| = |R|]
=> A 2 = 2A 2 + 2A 2 cosθ
=> cosθ = -1/2
=> θ = 120°
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