Two equal forces (P each )act at a point inclined to each other at angle of 120 degree.The magnitude of their resultant is :
a)P/2
b)P/4
c)P
d)2P
i only want the fastest method to solve this method because i have solved this already using resultant formula. any other faster methods?
Answers
Answered by
114
Hmm, you want fastest method .
you can do it fast when you know some special result.
There are .....
1. When two equal vectors A are inclined 90° then, resultant = √2A
2. When angle between two equal vectors A is 120° , then resultant = A
3. When angle between two equal vectors A is 180° , then resultant = 0
4. When angle between two equal vectors A is 60° , then resultant = √3A
Now, come to the question,
Your question is " two equal force inclined 120° ,
So, resultant = P
Just 1 second is enough for answering.
Well you know method is Resultant = √{P² + P² + 2P.PCos120°} = P
So, option (C) is correct.
you can do it fast when you know some special result.
There are .....
1. When two equal vectors A are inclined 90° then, resultant = √2A
2. When angle between two equal vectors A is 120° , then resultant = A
3. When angle between two equal vectors A is 180° , then resultant = 0
4. When angle between two equal vectors A is 60° , then resultant = √3A
Now, come to the question,
Your question is " two equal force inclined 120° ,
So, resultant = P
Just 1 second is enough for answering.
Well you know method is Resultant = √{P² + P² + 2P.PCos120°} = P
So, option (C) is correct.
Answered by
26
Answer:The ans. is P
Explanation:
=√ P^2 +P^2+2P^2×cos 120
=√2P^2+2P^2×(-1/2)
=√2P^2-P^2
=√P^2
= P
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