Two equal masses travel towards each other on a frictionless air track at speeds of 60 m/s and 40 m/s. They stick together on impact.
What are the speeds of the masses after impact?
Answers
Answered by
3
Answer:
Use conservaion of momentum, such as ,
Mv+MV=2M S , M is the mass of each one
V is 60 m?/sec, v= 40 m/ sec.
M(v+V)=2M S , so S =( v+V)/2=100/2= 50 m/ sec.
S is the velocity of the summed masses after collision.
Answered by
2
Answer:
10m/s
Explanation:
Mv+mv=2MS
but 40 is negative because they are coming in opposite direction
M=m
so, 60+(-40)=2S
20/2=S
10m/s=S
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