Two equal masses travel towards each other on a frictionless air track at speeds of 60 m/s and 40 m/s. They stick together on impact.
What are the speeds of the masses after impact?
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This is very simple to do using the principle of conservation of momentum. Let each mass be m . Arbitrarily adopting the standard that the first mass is travelling with a positive velocity, and the combined masses will be travelling with velocity v we get :-
2mv=60m−40m=20m
dividing both sides by 2m we get
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