Question

two equal point charges A and B are r distance apart. A third point charge placed on the perpendicular bisector at a distance d from the centre will experience maximum electrostatic force when
$(1)d = r \div 2 \sqrt{2}$
$(2)d = r \div \sqrt{2}$
$(3)d = r \times \sqrt{2}$
$(4)d = 2 \sqrt{2r}$

Answer 1

$(2)d=r\div2\sqrt{2}$