Question

two equal point charges A and Bare R distance apart. a third point charge placed on the perpendicular bisector at a a distance d from the center will experience maximum electrostatic force when

Answer 1

Answer:

A third point charge placed on the perpendicular bisector at a distance 'd' from the centre. Let charge on each particle is q and charge on third particle is Q. but only y = R/2√2 , d²F/dy² < 0 and force will be maximum. so, at y = R/2√2 electrostatic force will be maximum.