Question

two equal point charges each of 3micro coloumb separated by a certain distance in meters​

Answer 1

Answer:

Correct option is

A

16.2×10  

−3

N

The distance between two charges is r=  

(2−1)  

2

+(3−1)  

2

+(1−1)  

2

 

​

=  

5

​

 

By Coulomb's law, the force between two charges is F=  

4πϵ  

0

​

 

1

​

 

r  

2

 

q  

1

​

q  

2

​

 

​

=(9×10  

9

)(  

5

3×10  

−6

×3×10  

−6

 

​

)=16.2×10  

−3

N

Explanation: