Two equal positive point charges q are held a fixed distance
Answers
Explanation:
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question:Two positive charges +Q are held fixed a distance d apart. A particle of negative charge -q is placed midway between them, perpendicular to the line joining them .At what point along perpendicular bisector will it experience maximum force
answer:It should be placed at a distance of d/2 from the mid-point along the perpendicular bisector joining the 2 charges.
Reason: the -ve charge will experience maximum force if it is kept on the perpendicular bisector such that the line joining it & the +ve charges makes an angle of 45 degree with the line joining the two +ve charges.
If the -ve charge is kept at the mid point of the line joining the two charges the net force will be 0, bcoz the force experienced by the -ve charge due to the two +ve charges will be equal and in the opposite direction.