Two equal side of a triangle are each five meters less than twice the third side if the perimeter of the triangle is 55 meters find the length of its sides
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ABC is a triangle in which
AB=AC
Let third side be x m
According to question,
AB=AC= 2x-5
The perimeter of the triangle =
55 m
AB+BC+AC=55
2x-5+x+2x-5=55
5x-10=55
5x=55+10
5x=65
x=13
AB=AC=2x-5=2×13-5=21
AB=AC=21 m
BC=13m
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