Question

Two equal side of a triangle are each five meters less than twice the third side if the perimeter of the triangle is 55 meters find the length of its sides

Answer 1

ABC is a triangle in which

AB=AC

Let third side be x m

According to question,

AB=AC= 2x-5

The perimeter of the triangle =

55 m

AB+BC+AC=55

2x-5+x+2x-5=55

5x-10=55

5x=55+10

5x=65

x=13

AB=AC=2x-5=2×13-5=21

AB=AC=21 m

BC=13m