two equal side of an isosceles triangle are each 2 cm more than thrice the third side.if the perimeter of triangle is 67 cm, find the length of its side
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let third side be x.
and, according to question, one side and second side be 3x+2. now, x+ 3x+2 +3x+2 =67 ,5x +4=67, x= 63/5= 12.6 . so, third =12.6 cm and first and second side are 39.8 cm
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