Question

Two equal sides of a triangle are 1 m more than half the third side. if the perimeter of the thangle 22 m. Find he length of its sides.

Answer 1

Given :-

▪ A triangle with two of its sides equal and are 1 m more than half the third side.

▪ Perimeter of the triangle is 22 m.

To Find :-

▪ Length of the sides.

Solution :-

Given that the two sides of the triangle are equal, Therefore it is an isosceles triangel.

Let the third side be x , So the other two sides will measure x/2 + 1 m

Now, The perimeter is given to be 22 m,

We know, Perimeter is the sum of all sides of a geometric shape.

⇒ Perimeter = Sum of all sides

⇒ 22 = (x/2 + 1) + (x/2 + 1) + x

⇒ 22 = 2(x/2 + 1) + x

⇒ 22 = x + 2 + x

⇒ 22 = 2(x + 1)

⇒ 11 = x + 1

⇒ x = 10

Hence,

• The two equal sides are 6 m each.
• The third side is 10 m in length.

Answer 2

Answer:

$\huge\underbrace\mathscr\color{lime}{ Given࿐}$

• A triangle with two of its sides equal and are 1 m more than half the third side.

• Perimeter of the triangle is 22 m.

$\huge\underbrace\mathscr\color{lime}{ To \: find࿐}$

• Length of the sides.

$\huge\underbrace\mathscr\color{lime}{ Solution࿐}$

• Given that the two sides of the triangle are equal, Therefore it is an isosceles triangel.

Let the third side be x , So the other two sides will measure x/2 + 1 m

• Now, The perimeter is given to be 22 m, We know, Perimeter is the sum of all sides of a geometric shape.

$\green{ \underline{ \boxed{ \sf{Perimeter=\:Sum \: of \: all\: angles }}}}$

➟22 = (x/2 + 1) + (x/2 + 1) + x

➟22 = 2(x/2 + 1) + x

➟ 22 = x + 2 + x

➟22 = 2(x + 1)

➟11 = x + 1

➟ X= 10

Hence,

• The two equal sides are 6 m each.

• The third side is 10 m in length.