Question

Two equal sides of a triangle are 5 cm less than three times the third side. If perimeter of .
triangle is 53 cm, find the lengths of each side of the triangle​

Answer 1

Answer:

22,22,9

Step-by-step explanation:

Let the third side of the triangle be x.

Then,two equal sides are 3x-5

A/q

3x-5+3x-5+x=53

7x-10=53

7x=53+10

7x=63

x=63/7

x=9

Third side is 9 cm

And equal sides are 9×3-5=22

Answer 2

The sides of the triangle are 22, 22, and 9.

Given:

Two equal sides of a triangle are 5cm.

The perimeter of the triangle is 53cm.

To Find:

Length of each side of the triangle.

Solution:

Here, it is given that the two equal sides of a triangle are $5cm.$

let's suppose that the third side of the triangle is $x$.

so, the length of the other two equal sides will be $(3x-5)cm$.

here, the perimeter of the triangle = sum of all sides.

now, after putting the given values in the above formula,

we get,

$53=(3x-5)+(3x-5)+x$

$53=7x-10$

now,

$53+10=7x\\63=7x\\x=9$

here we get, the value of $x=9$

now, we will put the value of $x$ into $3x-5$

                                                           $=3\times 9-5\\=27-5\\=22$

Hence, the sides of the triangle are 22, 22, and 9.