Question

Two equal sides of a triangle are 5m less than twice the thrid side . If the perimeter of the triangle is 55 m , find the length of its sides

Answer 1

Let the third side be x
Then the two equal sides are 2x-5 each

According to the question
Perimeter = 55m
i.e.    x + (2x-5) + (2x-5) = 55m
         x + 4x - 10 = 55
         5x - 10 = 55
         5x = 65
         x = 13m

Required Sides are   (i)  x =13m  (ii)  2x-5 = 21m    (iii)   2x-5 = 21m

Answer 2

Given:

• Two equal sides of a triangle are 5m less than twice the thrid side .and the perimeter of the triangle is 55 m .

To Find:

• Length of its sides.

Solution:

Let the third side of ∆ be x.

Therefore, measure of another sides is (2x - 5).

★ Perimeter of ∆ = 55 m.

We know that, 

Perimeter of ∆ = sum of measure of its all sides.

→x + (2x − 5)+ (2x − 5) = 55

→5x −10 = 55

→5x = 55 + 10

→5x = 65

→x = 65/5

→x = 13m

Therefore, Measure of all sides of ∆ is, 

• 2 equal sides, 2x - 5 = 2 × 13 - 5 = 21 m
• Third side, x = 13 m

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