Question

Two equal sides of a triangle are each 4m less than three times the third side. Find the dimensions of the triangle, if the perimeter is 55m

Answer 1

GivEn:-

• Two equal sides of a triangle are each 4m less than three times the third side.

• Perimeter of triangle = 55m

To find:-

• Dimensions of the triangle

SoluTion:-

Lets the third side (c) of triangle be x m.

Given that,

Two equal sides of a triangle are each 4m less than three times the third side.

Therefore,

First (a) and second (b) side of triangle = (3x - 4) m

★ According to question:-

Perimeter to triangle = 55 m

→ a + b + c = 55 m

Now, Putting values of a, b and c:-

→ (3x - 4) + (3x - 4) + x = 55

→ 6x - 8 + x = 55

→ 7x - 8 = 55

→ 7x = 55 + 8

→ 7x = 63

→ x = 63/7

→ x = 9 m

★ Hence, The dimensions of triangle are:-

→ First side (a) = (3x - 4)

= ( 3 × 9 - 4)

= 23 m

→ Second side (b) = (3x - 4)

= (3 × 9 - 4)

= 23 m

→ Third side (c) = x

= 9 m

★ Hence Solved!!

_________________________

Answer 2

Given ,

• Two equal sides of a triangle are each 4m less than three times the third side

• The perimeter of triangle is 55 m

Let ,

The third side of triangle be x

Then , The measures of two equal sides of triangle = 3x - 4

We know that , the perimeter of triangle is given by

$\large \sf \fbox{Perimeter = A + B + C}$

Thus ,

55 = (3x - 4) + (3x - 4) + x

55 = 7x - 8

7x = 63

x = 63/7

x = 9

$\therefore \sf \underline{The \: measures \: of \: sides \: of \: triangle \: are \: 9 \: m , \: 23 \: m \: and \: 23 \: m}$