Question

Two equal sides of a triangle are each 4m less than three times thethird side. find the dimensions of the triangle, if its perimeter is55m.

Answer 1

$\textbf {Hey there, here is the solution.}$

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Define x:

Let the third side be x

The other 2 sides will be (3x - 4) each.

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Form equation and find x:

The perimeter is 55

Side 1 + Side 2 + Side 3 = Perimeter

(3x - 4) + (3x - 4) + x = 55

3x - 4 + 3x - 4 + x = 55

7x - 8 = 55

7x = 63

x = 9

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Find the dimension:

third sides = x = 9 m

the other 2 sides = 3x - 4 = 3(9) - 4 = 23 m

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Answer: The dimensions are 23m, 23m and 9 m

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⭐$\textbf {Cheers }$⭐

Answer 2

$\text {Your answer !!}$

Let a, b and c, three sides of a triangle whose $\textbf {perimeter = 55m}$

$\text{Let a = x}$

$\text{b = 3x - 4}$

$\text {c = 3x - 4}$

$\huge {Perimeter = a + b + c }$

$= > 55 = x + (3x - 4) + (3x - 4) \\ \\ = > 55 = x + 3x - 4 + 3x - 4 \\ \\ = > 55 = x + 3x + 3x - 4 - 4 \\ \\ = > 55 = 7x - 8 \\ \\ = > 55 + 8 = 7x \\ \\ = > 63 = 7x \\ \\ = > \frac{63}{7} = x \\ \\ = > 9 = x$

$\large {Hence, a = x = 9m}$

$\large {b = 3x - 4 = 3 × 9 - 4 = 27 - 4 = 23}$

$\large {c = 3x - 4 = 9 × 3 - 4 = 27 - 4 = 23}$

$\text {Thanks !!}$