Math, asked by kmlakshmitedlapu, 9 months ago

Two equal sides of a triangle are each 5 meters less than twice the third side. If the
perimeter of the triangle is 55 meters, find the length of its sides?
1190 dhe anales?​

Answers

Answered by inayat6365
0

Answer:

Let the 3rd, unequal side be x.

1st equal side = 2x-5

2nd equal side = 2x-5

Perimeter = Sum of all sides

55 = 2(2x-5) + x

55 = 4x - 10 + x

65 = 5x

x = 13

Thus, the length of the sides are 13m, 21m, and 21m.

Mark my answer as the brainliest please!

Answered by Darkrai14
108

ᏀᏆᏙᎬΝ:-

Two equal sides of triangle are 5 meters (each) less than twice of third side.

Perimeter of ∆ = 55 meters.

Ƭ០ ⨏ɨ⩎ᖱ:-

The length of the third side.

ՏϴᏞႮͲᏆϴΝ:-

Let the third side be x.

Then the two equal sides will be (2x-5) each.

\text{Perimeter of the triangle formula:-}

\sf side 1 + side 2 + side 3

Using the formula,

\sf (2x-5) + (2x-5) + x = 55

\sf \implies 2x - 5+2x-5+x=55

\sf \implies 5x - 10 = 55

\sf \implies 5x= 55+ 10

\sf \implies 5x= 65

\sf \implies x = \dfrac{65}{5} = 13

\sf \implies x = 13

____________________

Length of first side

= 2x - 5

= 2(13) - 5

= 26-5

= 21m

_____________________

Length of second side

Length of second side was equal to the first side so

Length of second side = 21m

_____________________________

Length of third side

Length of third side was x.

And we got the value of x as 13

So length of third side is 13m.

Hope it helps

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