Question

Two equal sides of a triangle are each 5 meters less than twice the third side. If the
perimeter of the triangle is 55 meters, find the length of its sides?
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Answer 1

Answer:

Let ABC be the required triangle. 

Let the third side be x m long

Two equal sides i.e AB= BC will be 2x-5

The perimeter of triangle ------- AB + BC + AC = 55

 

2x - 5 + 2x - 5 + x = 55

5x - 10 = 55

5x= 65

x= 13m 

So the other two sides will be 2* 13 - 5= 26 - 5 = 21m

Answer 2

Answer:

Let, third side of triangle be x.

According to the question,

Two equal side of triangle are 5 meters less than the third side.

So, the two equal side = (2x - 5) meters

Given : perimeter of triangle = 55 meters

=> sum of all sides of triangle = 55

=> (2x-5) + (2x-5) + x = 55

=> 5x - 10 = 55

=> 5x = 55 + 10

=> x = 65/5

=> x = 13

Therefore,

Third side = x = 13 meters

other two equal sides = (2x - 5)

= (2×13 - 5) = 21 meters

Step-by-step explanation: