Question

Two equal sides of a triangle are each 5 meters less than twice the thrid side. If the perimeter of the triangle is 55 meters,find the length of its side. ​

Answer 1

Answer:

Let the third side be x m.

Then the two equal sides are of length (2x−5) m.

Perimeter of triangle = 55 m.

⟹x+(2x−5)+(2x−5)=55

⟹5x−10=55

⟹x=13

Hence, the length of the triangle's sides are 13m, 21m and 21m.

Step-by-step explanation:

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Answer 2

☯ Let the third side of ∆ be x.

☯ Therefore, measure of another sides is (2x - 5).

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★ Perimeter of ∆ = 55 m.

We know that,

Perimeter of ∆ = sum of measure of its all sides.

$:\implies\sf x + (2x - 5) + (2x - 5) = 55$

$:\implies\sf 5x - 10 = 55$

$:\implies\sf 5x = 55 + 10$

$:\implies\sf 5x = 65$

$:\implies\sf x = \cancel{ \dfrac{65}{5}}$

$:\implies{\boxed{\frak{\pink{x = 13\;m}}}}\;\bigstar$

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☯ Therefore, Measure of all sides of ∆ is,

• 2 equal sides, 2x - 5 = 2 × 13 - 5 = 21 m

• Third side, x = 13 m

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$\qquad\qquad\qquad\boxed{\underline{\underline{\purple{\bigstar \: \bf\:More\:to\:know\:\bigstar}}}}$

• Area of right angle ∆ = $\sf \dfrac{1}{2} \times b \times h$

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• Area of ∆ using Heron's Formula = $\sf \sqrt{s(s - a)(s - b)(s - c)}$