Question

Two equal sides of a triangle are each 5 meters less than twice the third side.if the perimeter of rectangle is 55 meters .find the lengths of the sides

Answer 1

Let the length of third side be a units
length of equal sides = (2a -5) units
now, perimeter = 55
⇒a + (2a-5) +(2a-5) = 55
⇒5a =65
⇒a =13
so length of sides are 13 m, 21 m and 21 m


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Answer 2

Heya !!!



Let third side of a triangle be X m.




Each equal side = 2(X)-5 m


Perimeter of triangle = 55 m




2(2X -5) + X = 55



4X - 10 + X = 55


5X = 55+10



5X = 65



X = 65/5



X = 13 m



Third side = X = 13 m



Equal side = 2X-5 = 2 × 13-5 = 26-5 = 21 m



Hence,




21 m , 13 m and 21 m are the Length of side of a triangle.

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