Question

Two equal sides of a triangle are each 5 meters less than twice the third side. If the permeter of the triangle is 55 meters, find the length of its sides? ​

Answer 1

Given :-

Two equal sides of a triangle are each 5 meters less than twice the third side. If the perimeter of the triangle is 55 meters,

To Find :-

Length of sides

Solution :-

Let the unequal side be x

Then, equal side = 2x - 5

2x - 5 + 2x - 5 + x = 55

5x - 10 = 55

5x = 55 + 10

5x =  65

x = 65/5

x = 13

Sides of the triangle are

x = 13 m

x = 13 m

2x - 5 = 2(13) - 5 = 26 - 5 = 21 m

Answer 2

Answer:

Two equal sides of a triangle are each 5 meters less than twice the third side. If the perimeter of the triangle is 55 meters, what is the length of its sides?

Make a List of the Given facts:

Let X = third side of triangle

Triangle w/ 2 equal sides = twice third -5 = 2X - 5

units = meters

Perimeter = 55 meters

Find: length of sides.

Plan: Use Perimeter concept ( sum of sides) to get an equation. It will connect the “given” facts to what needs to the “find”.

X + (2X - 5) + (2X - 5) = 55 Solve for X

5X - 10 = 55. Combine like terms

5X = 65 Add 10 to both sides of the equation

X = 13 m

Therefore: the 3 sides of the triangle are:

13 m, 21 m, 21 m

Double Check: 13 + 21 + 21 = 55 ✅

Answer: Sides = 13 m, 21 m, 21 m

Step-by-step explanation:

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