Two equal sides of a triangle are each 5 meters less than twice the third side.if the perimeter of the triangle is 55m find the length of two sides
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2x-5+2x-5+x =55
5x=65
x=13. third side
2x-5=21m ans
5x=65
x=13. third side
2x-5=21m ans
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Answered by
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♠ ANSWER :
❇ ACCORDING TO THE QUESTION,
Let two equal sides be x m each.
And third side be y.
Then, x = 2y - 5. [ First side ]
x = 2 y - 5. [ Second side]
Perimeter of triangle = 55 m.
Perimeter of triangle = x + x + y. [ Sum of length of all three sides. ]
2y - 5 + 2 y - 5 + y = 55
4 y - 10 + y = 55
5 y = 55 + 10
y = 65 / 5
y = 13 m.
⏺️First side = 2y - 5
2 ( 13 ) - 5 = 26 - 5 = 21 m.
⏺️Second side = 21 m.
⏺️Third side = 13 m.
❇ ACCORDING TO THE QUESTION,
Let two equal sides be x m each.
And third side be y.
Then, x = 2y - 5. [ First side ]
x = 2 y - 5. [ Second side]
Perimeter of triangle = 55 m.
Perimeter of triangle = x + x + y. [ Sum of length of all three sides. ]
2y - 5 + 2 y - 5 + y = 55
4 y - 10 + y = 55
5 y = 55 + 10
y = 65 / 5
y = 13 m.
⏺️First side = 2y - 5
2 ( 13 ) - 5 = 26 - 5 = 21 m.
⏺️Second side = 21 m.
⏺️Third side = 13 m.
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