Question

two equal sides of a triangle are each 5 metre less than twice the third third side if the perimeter of the triangle is 55 metre find the length of its side ​

Answer 1

Answer:

• Sides of triangle are 21 m, 21m and 13 m.

Step-by-step explanation:

Given :-

• Perimeter of triangle is 55 m.

To find :-

• Length of its side.

Solution :-

Let, Measure of third side be x m.

And, Measure of other two equal sides be 2x - 5 m. [Equal sides of triangle are each 5 m less than twice the third side]

We know,

Perimeter of triangle = Sum of all sides.

So, Put the values :

$\rightarrow$ Perimeter = 2x - 5 + 2x - 5 + x

$\rightarrow$ 55 = 2x - 5 + 2x - 5 + x

$\rightarrow$ 55 = 5x - 10

$\rightarrow$ 55 + 10 = 5x

$\rightarrow$ 65 = 5x

$\rightarrow$ 65/5 = x

$\rightarrow$ x = 13

Now,

Sides :-

Two equal sides = 2x - 5 = 2×13 - 5 = 21. Thus, Measure of two equal side is 21 m.

Third side = x = 13. So, Measure of third side is 13 m.

Therefore,

Sides of triangle are 21 m, 21 m and 13 m.

Answer 2

$\tt \huge \underline \red{AnswEr:-}$

Let the third side be x metre

According to question,

Other two sides are (2x-5) metre each .

Now,

$\sf \implies \purple{2x - 5 + 2x - 5 + x = 55}$

$\sf \implies \purple{5x - 10 = 55}$

$\sf \implies \purple{5x = 55 + 10}$

$\sf \implies \purple{5x = 65}$

$\sf \implies \purple{x = \frac{ \cancel{65} \: 13}{ \cancel5} }$

$\sf \implies \purple{x = 13} \: m$

Thus other two sides are (2*13)-5=21 m

$\therefore \tt \green{the \: \: length \: \: of \: \: the \: \: triangle \: \: sides \: \: are \: \: 13m \: \: and \: \: other \: two \: \: sides \: \: are \: \: 21m \: \: each}$