Question

two equal sides of a triangle are each 5 metres less than twice the third side if the perimeter of the triangle is 55 metres find the length of its sides ​

Answer 1

Answer:

equal sides Xeach

3rd Side=y

x=2y-5

perimeter

(2y-5) 2+y=65

4y-l0+y=55

5y=65,y=13

x = 2 y-5

x = 26-5=21

sides are21, 21 and 13m

Answer 2

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\:Solution:-\:\:\:}}}}}}$

Required answer:

• The lengths of the sides are 13 m, 21 m, 21 m.

Given Information:

• Two equal sides of a triangle are each 5 metres less than twice the third side if the perimeter of the triangle is 55 metres.

Need to find out:

• The lengths of the sides = ?

$\underline{\underline{\underline{\underline{\mathfrak{\pink{ \:\:\: Explanation:-\:\:\:}}}}}}$

Let the third side of the triangle be y metres.

Then,

• The two equal sides will be (2y - 5) m each.

According to the problem,

Perimeter of ΔABC = AB + BC + CA

Perimeter of ΔABC = 55 m

Therefore,

=> 2y - 5 + y + 2y - 5 = 55

=>⠀⠀⠀⠀⠀⠀⠀⠀5y - 10 = 55

=> ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ 5y = 65

=> ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ y = 13 m

So,

• Third side = 13 m

=> Other two sides = 2 × 13 - 5

=> Other two sides = 26 - 5

=> Other two sides = 21 m

Therefore,

• The sides are 13 m, 21 m, 21 m

$\underline{\underline{\underline{\underline{\mathfrak{\blue{ \:\:\: Check:-\:\:\:}}}}}}$

=> 13 + 21 + 21

=> 13 + 42

=> 55 m is the perimeter of ΔABC.