Question

Two equal sides of a triangle are each 5 metres less than twice the third side
perimeter of the triangle is 55 metres, find the length of the sides
29. Two complementary angles differ by 8° Find the angles,​

Answer 1

Step-by-step explanation:

given

two equal sides of a triangle are each 5m

less than twice the third side

let

two sides of a triangle=2x-5

and third side of a triangle=X

A. T. Q

perimeter of triangle=sum of all sides of triangle

=>2x-5+2x-5+X=55

=>5x-10=55

=>5x=55+10

=>5x=65

=>X=13

so sides of triangle are

two equal bsides of a triangle=2x-5

=2*13-5

=21m

and third side of a triangle=13m

question 29

let the first Angle be 90-X

and 2nd be x

A T. Q

=>90-X-X=8

=>-2X=8-90

=>2X=82

=>X=41

SO

first Angle=90-x

=90-41

=49

2nd angle=41

Answer 2

$\bold{\underline{\red{Question \::}}}$

Two equal sides of a triangle are each 5 metres less than twice the third side perimeter of the triangle is 55 metres, find the length of the sides.

$\bold{\underline{\red{Solution \::}}}$

Let the -

• third side be "M" m

Two equal sides of triangle are each 5 m less than twice the third side.

So,

Two equal sides = (2M - 5) m

Also, given that perimeter of triangle is 55 m

Now,

Perimeter of triangle = Sum of three sides

=> 55 = 2M - 5 + 2M - 5 + M

=> 55 = 5M - 10

Take 5 common from both sides

=> 5(11) = 5(M - 2)

=> 11 = M - 2

=> 11 + 2 = M

=> M = 13

So,

Third side is 13 m

Two equal sides = 2(13) - 5

=> 26 - 5

=> 21 m

•°• Length of two equal sides of traingle are 21 m and length of third side is 13 m

$\bold{\underline{\red{Question \::}}}$

Two complementary angles differ by 8°. Find the angles.

$\bold{\underline{\red{Solution \::}}}$

Let the -

• one angle be "M"

So,

Other angle is (90 - M)

According to question,

=> M - (90° - M) = 8°

=> M - 90° + M = 8°

=> 2M = 98°

=> M = 49°

So,

Other angle = 90° - 49°

=> 41

•°• Angles are 41° and 49°