Two equal sides of a triangle are each 5 metres less than twice the third side. If th. pertmeter of the triangle is 55 metres, find the lengths of its sides.
Answers
Step-by-step explanation:
let the two equal sides be x
and third side be y
according to first condition,
x=2y-5
x-2y= -5 ..........(1)
according to second condition,
perimeter = sum of all sides= 55
1st side+ 2nd side+ 3rd side= 55
x+x +y= 55
2x+y=55 ........(2)
multiplYing 2 in frst equation and solving them simultaneously
2x-4y= -10
2x+y= 55
- - -
__________
-5y= -65
y= 13
substituting this in equation (1)
x-2y = -5
x-2(13)= -5
x-26 = -5
x= -5+26
x= 21
thus the two equal sides are 21 metre and third side is 13 metre .
Answer:
The lengths of three sides of the triangle are 13m, 21m and 21 m.
Given:
➛Two equal sides of a triangle are each 5 metres less than twice the third side.
➛The pertmeter of the triangle is 55 metres.
To Find :
The lengths of three sides of the triangle.
Solution:
We are given,
➛Two equal sides of a triangle are each 5 metres less than twice the third side.
➛The pertmeter of the triangle is 55 metres.
Let the third side of the triangle be m.
therefore,
Two equal sides of the triangle are
➛( 2m - 5 ) and ( 2m - 5 )
Perimeter = Sum of sides
but, perimeter of the triangle = 55 m . ( given )
➞ m + ( 2m - 5 ) + ( 2m - 5 ) = 55
➞m + 2m - 5 + 2m - 5 = 55
➞5m - 10 = 55
➞5m = 55 + 10
➞5m = 65
➞m = 65 / 5
m = 13 m
hence,
the two equal sides are
➞[ ( 2×13 ) - 5 ] ➛ 26 - 5 ➛ 21
hence the lengths of three sides of triangle are 13 m , 21 m and 21 m.