two equal sides of a triangle are each 5 metres less than third side.if the perimeter of the triangle is 55 metres, find the length of its sides
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Answered by
1
Let 3rd side be x, then 3 sides will be x, x-5 and x-5
Given perimeter=55
X+(x-5)+(x-5)=55
3x-10=55
3x=65
X=65/3
X=21.67(approx.)
Therefore, three sides are 21.67m, 16.67m and 16.67m
Given perimeter=55
X+(x-5)+(x-5)=55
3x-10=55
3x=65
X=65/3
X=21.67(approx.)
Therefore, three sides are 21.67m, 16.67m and 16.67m
Answered by
1
let the side be 'x'
equal sides = 'x-5' each
=>x+x-5+x-5 = 55
=>3x-10=55
=>3x-=65
=>x=65/3
=>x=21.67
equal sides=16.67
equal sides = 'x-5' each
=>x+x-5+x-5 = 55
=>3x-10=55
=>3x-=65
=>x=65/3
=>x=21.67
equal sides=16.67
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