Question

Two equal sides of a triangle are each 5m less than twice the third side. If the perimeter of the triangle is 55m, find the lengths of its sides.

Answer 1

equal sides = a and b.
a = b = 2 c - 5
perimeter = a + b + c  =  2c-5+ 2c - 5 + c =3c - 10
Hence    3c -10  = 55 meters
3c = 65 meters
c = 65/3 meters
a = b = 130/3 -5  = 115/3 meters

Answer 2

Let the third side of triangle be x m.

Then,

Two equal sides of the triable = (3x-4) m.

Given:

Perimeter of the triangle - 55 m

Therefore,

Perimeter of the triangle = Sum of the sides of the triangle

so,

x + 3x - 4 + 3x = 55

$\implies$ 7x - 8 = 55

$\implies$ 7x = 55 + 8

$\implies$ 7x = 63

$\implies$ x = 63/7

$\implies$ x = 9

$\boxed{x = 9}$

Hence,

The dimensions of the triangle are 9m,

3*9 - 4 = 23,

3*9 - 4 = 23

All sides are 9m, 23m, 23m