Two equal sides of an isoceles triangle are each 2cm more than thrice of first side. If the perimeter of the triangle is 67 cm, find the lengths of it's sides.
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let 1 side be=x
other two sides = 2+3x , 2+3x
perimeter of triangle = sum of all sides
67= x + 2+3x + 2+3x
67=7x+4
7x = 67-4
7x=63
x=9
length of 1 side =9 cm
length of other 2 sides =29, 29
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