Question

two equal sides of an isosceles traingle are each 2 cm more than thrice the third side .if the perimeter of the traingle is 67 cm. find its length of sides....with process​

Answer 1

Let each side be x

one equal side = 3x + 2

(3x + 2) x 2 + x = 67

7x + 4 = 67

7x = 67 - 4 = 63

x = 63 / 7 = 9

equal side = 3 x 9 + 2 = 27 + 2 = 29

third side = 9

Answer 2

a=29cm , b= 29cm and c= 9 cm

lets put the sides as a,b and c

now lets say a and b are the two equal sides

and c is third side

so...   a= (2+3c) and b = (2+3c)

solve:

a + b + c= 67cm

substitute a  and b  with (2+ 3c)

(2+3c) + ( 2+ 3c) + c = 67

4+ 7c= 67

take 4 to the other side by doing the opposite operation

7c = 67 - 4

7c = 63

now divide by seven both sides

c= 9cm

a= 2+ 3(9)= 29cm

b= 2+ 3(9)= 29 cm