Two equal sides of an isosceles triangle are 10 cm and the perimeter is 28 cm, then the area of the triangle is
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Answered by
28
Given :
- Equal sides of triangle = 10 cm
- Type of Triangle = Isosceles
- Perimeter of triangle = 28 cm
To Find :
- Area of the Triangle = ?
Solution :
~ Formula Used :
- Perimeter of Triangle :
- Area of Triangle :
Where :
- ➢ s = Semi - Perimeter
- ➢ a = Side 1
- ➢ b = Side 2
- ➢ c = Side 3
~ Calculating the 3rd Side :
~ Calculating the Area :
- Semi - Perimeter :
- Area :
~ Therefore :
❝ Area of the given Triangle is 36.664 cm² . ❞
Answered by
6
To find : area of isosceles triangle .
Given : two equal sides =
Perimeter =
Solution :
- Let , a, b , c be the sides of isosceles triangle .
- We know that , formula for perimeter of triangle is -
- Then,
- We find area of triangle by Heron's Formula :
- Where, s = semi perimeter and ,a, b, c are sides of triangle
- Putting values , we get
Area =
Hence , area of given isosceles triangle is
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