Two equal sides of an isosceles triangle are (3×-1) units and ( 2×+2) units . The third side is 2× units . Find × and the perimeter of the triangle.
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Answer:45
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If the two equal sides are 3x-1 and 2x+2, then:
3x-1 = 2x+2 Subtract 2x from both sides.
x-1 = 2 Add 1 to both sides.

The perimeter (P) is found by adding the lengths of the three sides.
P = (3x-1)+(2x+2)+2x Substitute x = 3.
P = (3(3)-1)+(2(3)+2)+2(3)
P = (8)+(8)+(6)
P = 22
The perimeter is 22
3x-1 = 2x+2 Subtract 2x from both sides.
x-1 = 2 Add 1 to both sides.

The perimeter (P) is found by adding the lengths of the three sides.
P = (3x-1)+(2x+2)+2x Substitute x = 3.
P = (3(3)-1)+(2(3)+2)+2(3)
P = (8)+(8)+(6)
P = 22
The perimeter is 22
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