Question

Two equal sides of an isosceles triangle are 5y-2 and 4y +9 units.The third side is 2y +5 units.find y and the perimeter of the triangle.

Answer 1

Answer:

Step-by-step explanation:

5y-2=4y+9

5y-4y=9+2

y=11

perimeter=5y-2+4y+9+2y+5

               =11y+12

               =11*11+12

               =121+12

              =133

Answer 2

The perimeter of triangle would be 133 units.

Step-by-step explanation:

Since we have given that

Equal sides:

$5y-2$ and $4y+9$

Length of third side = 2y+5

Since above two sides are equal.

$5y-2=4y+9\\\\5y-4y=9+2\\\\y=11\ units$

Length of first side = $5y-2=5(11)-2=55-2=53\ units$

Length of second side = $4(11)+9=44+9=53\ units$

Length of third side = $2(11)+5=22+5=27\ units$

Perimeter of triangle would be

$53+53+27=133\ units$

Hence, the perimeter of triangle would be 133 units.

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The sides of a triangle are 12,13 and its perimeter is 50.Find the third side of the triangle?

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