Question

two equal sides of an isosceles triangle are each 2 centimetre more than thrice the third side if the perimeter of triangle is 67 cm find the length of its sides

Answer 1

x + z + x = 67
x = 2 + z
2+z+2+z+z = 67
4+3z = 67
z = 21

Answer 2

ATQ, the two equal sides of the isosceles triangle are each 2cm more than thrice of the third side.

let the third side of the isosceles triangle be x.

therefore the two other equal sides are 3x + 2

perimeter of the triangle is given = 67cm

therefore x + 3x + 2 + 3x + 2 = 67cm

==> 7x + 4 = 67cm

==> 7x = 67 - 4

==> 7x = 63

==> x = 63/7

==> x = 9

hence, length of the sides of the isosceles triangle are :-

=> x = 9cm

=> 3x + 2 = ( 3 × 9 ) + 2 = 27 + 2 = 29cm

=> 3x + 2 = 29cm

HOPE THIS HELPS..!!