two equal sides of an isosceles triangle are each 2 cm more than thrice the third side if the perimeter of triangle is 67 cm find the length of its sides
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let the lenght of the third side be x.
then remaining two equal sides are 3x+2 , 3x+2.
perimeter of a trainagle = sum of three sides
as per the problem,
x+3x+2+3x+2 = 67
7x + 4 = 67
7x = 67 - 4
7x = 63
x = 63/7
x = 9.
therefore sides are 9 cm ,(3*9+2)cm,(3*9+2)cm = 9 cm, 29cm, 29cm
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