Math, asked by divya858779, 9 months ago

Two equal sides of an isosceles triangle are each 2 cm more than thrice the third side. If the perimeter of triangle is 67 cm, find the lengths of its sides.​

Answers

Answered by ƦαíηвσωStαƦ
18

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  • Third side of rectangle = 9 Cm

  • Second side of rectangle = 29 Cm

  • First side of rectangle = 29 Cm

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\sf{\underline{\green{Given:-}}}

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  • Two equal sides of an isosceles triangle are each 2 cm more than thrice the third side. If the perimeter of triangle is 67 cm.

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\sf{\underline{\green{Find:-}}}

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  • Find the lengths of its sides.

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\sf{\underline{\green{Explanation:-}}}

Let the third side be y.

\:\:\:\:\dag\bf{\underline{\underline \red{Then:-}}}

  • First Side = (3y + 2)
  • Second Side = (3y + 2)

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\:\:\:\:\dag\bf{\underline{\underline \red{As\:we\:know\: that:-}}}

\small\pink{\underline {\boxed{\sf\pink{ Perimeter\:of\:a\:\triangle = Sum\:of\: three\: sides } }}}

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\longrightarrow \sf {y + (3y + 2) + (3y + 2) = 67}

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\longrightarrow \sf {y + 2 \times (3y + 2) = 67}

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\longrightarrow \sf {y + 6y + 4 = 67}

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\longrightarrow \sf {7y = 67 - 3}

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\longrightarrow \sf {7y = 63}

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\longrightarrow \sf {y = \cancel\dfrac{63}{7} }

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\longrightarrow \sf {y = 9}

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\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}

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  • Third side of rectangle = 9 Cm

  • Second side of rectangle = 3 × 9 + 2
  • Second side of rectangle = 29 Cm

  • First side of rectangle = 3 × 9 + 2
  • First side of rectangle = 29 Cm

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Answered by rsagnik437
88

Given:-

☆Two equal sides of an isosceles triangle are 2cm more than thrice the third side.

☆Perimeter of the triangle=67cm

To find:-

☆Length of the sides of the triangle

Solution:-

=>Let the third side of the triangle be x cm

=>Thus,the other two equal sides=(3x+2)cm

We know that:-

=>Perimeter of a triangle=Sum of 3 sides

Now:-

=>x + (3x+2) + (3x+2) = 67

=>x + 2(3x+2) = 67

=>x + 6x +4 = 67

=>7x = 67-3

=>7x=63

=>x=63/7

=>x=9

Thus,the sides of the triangle are:-

9cm

3×9+2=29cm

3×9+2=29cm

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