two equal sides of an isosceles triangle are each 2 cm more than thrice the third side if the perimeter of triangle is 67 centimetre find the length of its sides
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HELLO DEA........
LET THE SIDE BE = 2×+2×+×...
P=67
NOW
3X+4=67
3×=63
×=21
$!DE R.....23..23...21
HOPE IT VLL HELP UH. ..
MARK IT AS BRAINLIST ANSWER. ..
THANKS YOU ☆☆☆
LET THE SIDE BE = 2×+2×+×...
P=67
NOW
3X+4=67
3×=63
×=21
$!DE R.....23..23...21
HOPE IT VLL HELP UH. ..
MARK IT AS BRAINLIST ANSWER. ..
THANKS YOU ☆☆☆
Answered by
2
Answer:
Let the sides of the triangle be 3x, 2+3x, 2+3x
Step-by-step explanation:
Perimeter= 67 cm
3x+2+3x+2+3x= 67
9x+4= 67
9x= 67-4= 63
x= 63/9= 7
Sides:
3x= 3*7= 21 cm
2+3x= 2+21= 23 cm
Therefore the sides of the triangle are 21 cm, 23 cm, 23 cm.
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