Question

two equal sides of an isosceles triangle are each 2cm more than thrice the third side.if the perimeter of triangle is 67cm find the length of its sides​

Answer 1

Answer:

(3x+2)+(3x+2)+x=67

7x+4=67

7x=67-4

7x=63

x= 9cm

Answer 2

Step-by-step explanation:

Let the third side be 'X'cm

So, the equal sides are 'X + 2'cm

given perimeter of triangle=67 cm

s+s+s=67

x+(x+2)+(x+2)=67

x+x+2+x+2=67

3x+4=67

3x=67-4

3x=63

x=63/3

x=21

x+2=21+2=23

therefore, in an isosceles triangle equal sides are are 23 cm and the third side is 21 cm.