two equal sides of an isosceles triangle are each 2cm more than thrice the third side if perimeter is 67 cm find length its sidea
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Answered by
3
let the third side be x
and other sides be of length y
as per question
2x=y+2
=>2x-2=y----------------------------(i)
Also,
x+y+y=67
=>x+2x-2+2x-2=67
=>5x-4=67
=>5x=67-4
=>x=63/5
and other sides be of length y
as per question
2x=y+2
=>2x-2=y----------------------------(i)
Also,
x+y+y=67
=>x+2x-2+2x-2=67
=>5x-4=67
=>5x=67-4
=>x=63/5
Answered by
2
Let the third side be x.
Then the other 2 sides are (2+x) cm each.
By the problem,
perimeter = 67 cm.
67 = x +2 + x +2 + x
67= 3x + 5
67-5=3x
x = 62/3
= 20.67 cm approximately.
Thus, the sides are 20.67 cm, 22.67 cm and 22.67 cm.
Then the other 2 sides are (2+x) cm each.
By the problem,
perimeter = 67 cm.
67 = x +2 + x +2 + x
67= 3x + 5
67-5=3x
x = 62/3
= 20.67 cm approximately.
Thus, the sides are 20.67 cm, 22.67 cm and 22.67 cm.
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