Question

two equal sides of an isosceles triangle are is 2 cm more than 3 III if the perimeter of a triangle 73 cm find the length of its sides​

Answer 1

✬ Third Side = 23 cm ✬

✬ Equal Sides = 25 cm ✬

Step-by-step explanation:

Given:

• Two sides of an isosceles triangle is 2 cm more than 3rd side.
• Perimeter of triangle is 73 cm.

To Find:

• What is the length of all sides of triangle ?

Solution: Let the measure of third side of isosceles triangle be x. Therefore,

➟ Length of other two sides = 2 cm more than x

• Two sides of an Isosceles triangle are equal to each other.

➟ Length of other two sides = (x + 2) cm

As we know that

★ Perimeter of ∆ = Sum of all sides ★

A/q

• 3st side = x cm
• 2nd and 1st side = (x + 2) cm
• Perimeter is 73 cm.

$\implies{\rm }$ 73 = x + x + 2 + x + 2

$\implies{\rm }$ 73 = 3x + 4

$\implies{\rm }$ 73 – 4 = 3x

$\implies{\rm }$ 69 = 3x

$\implies{\rm }$ 69/3 = x

$\implies{\rm }$ 23 = x

So, Measure of

➛ 3rd side is x = 23 cm

➛ Equal sides are x + 2 = 23 + 2 = 25 cm

____________________

★ Verification ★

➨ 73 = 25 + 25 + 23

➨ 73 = 50 + 23

➨ 73 = 73

$\large\bold{\texttt {Verified }}$

Answer 2

Correct Question:

Two equal sides of an isosceles triangle are is 2 cm more than third side. If the perimeter of a triangle 73 cm find the length of it's sides.

Answer:

The length of the sides of isosceles triangle are 23 cm, 25 cm and 25 cm respectively.

Step-by-step explanation:

Perimeter of triangle = Sum of it's all sides

Assume that the third side of the triangle is x cm. Therefore, the other two sides are (x + 2) cm.

Perimeter of triangle = Sum of (first side + second side + third side)

Simply substitute the values,

→ 73 = (x + 2) + (x + 2) + x

→ 73 = x + 2 + x + 2 + x

→ 73 = 3x + 4

→ 73 - 4 = 3x

→ 71 = 3x

→ 69 = 3x

Divide by 3 on both sides,

→ 69/3 = 3x/3

→ 23 = x

Hence, the

• first side = x = 23 cm
• second side = x + 2 = 23 + 2 = 25 cm
• third side = x + 2 = 23 + 2 = 25 cm