Question

two equal sides of an isoscles triangle are each 2 cm more than thrice the third side. If the perimeter of triangle is 67 cm, find the lengths of its sides?

Answer 1

Hi Friend,

Here is your answer,

Let the third side be x.
So, the other two sides will be (2+x)

According to the Sum,

Perimeter(P) => 67 cm.

67 => x +2 + x +2 + x

67=> 3x + 5

67-5=>3x

x => 62/3

= (3x + 2) + (3x + 2) + x = 67


Hope it helps you!

Answer 2

Answer:

First of all, here the one who had answered 1st and have maths Aryabhatta rank, have given wrong answer, here we need to find the length of its sides, but I'll provide you the correct answer

The length of its sides are 29cm 29cm and 9cm.

Step-by-step explanation:

Let the sides of triangle be = x cm

Third side of the triangle be = y cm

Now,

= x = 3y + 2 (i)

Perimeter of the triangle = 67 cm = x + x + y = 67 cm = 2x + y = 67 cm

From equation (i)

= 6y + y + y = 67

= 7y + y = 67

= y = 9 cm

From equation (i)

= x = 3y + 2

= 3 × 9 + 2 = 29 cm

• Hence, the length of its sides are 29 cm, 29 cm and 9 cm