Question

two equal sides of an isoscles triangle are each 2 cm more than thrice the third side.if the perimeter of triangle is 67 cm,find the length of its sides

Answer 1

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Answer 2

Let the unequal side be a cm

Each equal side = 3a + 2 cm

Perimeter = 2(3a +2) + a

=> 67 = 6a + 4 + a

=> 63 = 7a

=> a = 9



First side = 3a + 2 = 3 × 9 + 2 = 27 +2 = 29 cm

Second side = 3 × 9 + 2 = 27 + 2 = 29 cm

Third side = 9 cm