two equal sides of an isoscles triangle are each 2 cm more than thrice the third side. if the perimeter of triangle is 67 cm,find the length of ots sides.
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Answered by
2
it is very easy.
Assume third side is x
so, equal sides are 3x+2.
so we can write...
x+3x+2+3x+2=67
ie. x=67/6
so sides are 67/6,71/6,71/6
Assume third side is x
so, equal sides are 3x+2.
so we can write...
x+3x+2+3x+2=67
ie. x=67/6
so sides are 67/6,71/6,71/6
Answered by
2
#RAM RAM ji ❤
ĀNSWĒR ⏬⏬
✔Let the one side of triangle be x
According to question
two other side are 3x+2 ------equation 1 .
Perimeter ▶67 cm(GiVen )
Now,
x+3x+2+3x+2=67
7x+4=67
7x=67-4
7x=63
x= 9 cm
So, one side of triangle is 9cm i.e x=9cm
hence,
put value of x in equation 1
so,
other two sides are ▶
3x +2
=18+2
=20cm
THANKS ✌☺
#DILDAAR NAVI ❤
ĀNSWĒR ⏬⏬
✔Let the one side of triangle be x
According to question
two other side are 3x+2 ------equation 1 .
Perimeter ▶67 cm(GiVen )
Now,
x+3x+2+3x+2=67
7x+4=67
7x=67-4
7x=63
x= 9 cm
So, one side of triangle is 9cm i.e x=9cm
hence,
put value of x in equation 1
so,
other two sides are ▶
3x +2
=18+2
=20cm
THANKS ✌☺
#DILDAAR NAVI ❤
Awnishshrivastava:
thanks
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