Question

two equal sides of an isoscles triangle are each 2cm more than thrice the third side .perimeter of triangle is 67cm find the length of its sides

Answer 1

(2+3x)+(2+3x)+x=67
4+7x=67
x=(67-4)/7
x=9

Answer 2

let third side =x cm
then equal 2 sides =3x + 2
3x+2+3x+2+x =67
or. 7x+4 = 67
or. 7x= 67-4
or. 7x=63
x=63/7=9
third side = x= 9
2equal side = 3x+2=3×9+2=27+2 =29