two equal sides of the triangle are 5 metres less than twice the third side of the perimeter of the triangle is 55 M find the length of its sides
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let the third side be x
the the other two equal sides=2x-5
Given
perimeter of the triangle=55m
ATQ
2x-5+2x-5+x=55m
5x-10=55
5x=55+10
5x=65
x=13
so the first and second side =2×13-5
=26-5
=21
the the other two equal sides=2x-5
Given
perimeter of the triangle=55m
ATQ
2x-5+2x-5+x=55m
5x-10=55
5x=55+10
5x=65
x=13
so the first and second side =2×13-5
=26-5
=21
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