Question

two equal squares of side 27.4 cm are fitted to form one rectangle. what is :
a)the area of one square?
b)the area of the rectangle formed by the two squares?
c)the perimeter of one square?
d)the perimeter of the rectangle formed by the two squares?

Answer 1

a) area of square= side *side
area of one square = 27.4*27.4
= 750.76cm sq
b) the rectangle formed will have
length= 27.4 + 27.4
= 54.8
breadth = 27.4
so
area of rectangle = length* breadth
= 54.8*27.4
=1501.52 cm sq
c) perimeter of square= 4*side
side of square= 27.4
so
perimeter of square=4*27.4
=109.6 cm
d) perimeter of rectangle= 2(l+b)
= 2(54.8 +27.4)
= 2(82.2)
=164.4cm

Answer 2

a)

area of a square
27.4×27.4
750.56 cm square

b)

length of the rectangle formed by two squares
54.8 cm

breadth of the rectangle formed by two square
27.4 cm

area of rectangle
54.8×27.4
1501.52 cm square

c)

perimeter of a square
27.4×4
109.6 cm

d)

length
27.4 cm

breadth
54.8 cm

perimeter of rectangle
2(27.4+54.8)
2×82.2
137 cm


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