Question

two equal sums of money were lent at s.i 11%p.a for 3½ years and 4½ years respectively. if the differences in interests for two perioeds was rs412.50 find each sum​

Answer 1

Answer:

Step-by-step explanation:

Let each sum be x.

Given that rate of interest is 11%

Now according to the question-

100×2

x×11×9

​  

−  

100×2

x×11×7

​  

=412.5

99x−77x=412.5×200

⇒22x=82500

⇒x=  

22

82500

​  

=3750

Hence the value of each sum is Rs.3750.