two equal sums of money were lent at s.i 11%p.a for 3½ years and 4½ years respectively. if the differences in interests for two perioeds was rs412.50 find each sum
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Answer
Let each sum be x.
Given that rate of interest is 11%
Now according to the question-
100×2x×11×9−100×2x×11×7=412.5
99x−77x=412.5×200
⇒22x=82500
⇒x=2282500=3750
Hence the value of each sum is Rs.3750.
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