Question

Two equal sums of money were lent at simple interest at 11% p.a. for 3½years and 4½ years
respectively. If the difference in interests for two periods was ₹412.50, find each sum.​

Answer 1

Step-by-step explanation:

R%=11

time is 3 1/2 4 1/2

difference between the interests =rs 412.50.

let the sum of two interests be X

Then we should follow the equation as below:

• 11×9/2×X÷100-11×7× X÷100 = 412.50
• from the above equation we get the X as 3750.hence we can say that the principal is 3750.
• verification:
• 3750×99/200-3750×77/200
• 371250/200-288750/200
• 371250-28850/200
• 412.50