Math, asked by tapashmalaker, 1 year ago

Two equal sums were borrowed at 8% simple interest per annum for 2 years and 3 years respectively. The difference in the interest was Rs.56. the sum borrowed were
1) 700/-
2) 690/-
3) 780/-
4) 740/-

Answers

Answered by rinita1
8
the sum borrowed is option.1) and the reason is above.
Attachments:
Answered by DelcieRiveria
5

Answer:

The correct option is 1.

Step-by-step explanation:

Let the two equal sums be x.

It is given that the two equal sums were borrowed at 8% simple interest per annum for 2 years and 3 years respectively.

Formula for interest is

I=\frac{P\times r\times t}{100}

Where, P is principal, r is interest rate, t is time in years.

Interest on first sum is

I_1=\frac{x\times 8\times 2}{100}=\frac{16x}{100}

Interest on second sum is

I_2=\frac{x\times 8\times 3}{100}=\frac{24x}{100}

The difference in the interest was Rs.56.

I_2-I_1=56

\frac{24x}{100}-\frac{16x}{100}=56

\frac{8x}{100}=56

x=\frac{5600}{8}

x=700

Therefore the sum borrowed were 700 and correct option is 1.

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